Directions for Ques.(1-2) : These questions are based on the following information.
The Venn diagram below shows the number of students who study Mathematics, Physics, Chemistry and Biology. The total number of students studying the subjects in the given order is 64, 76, 63, and 72 respectively.

1.How many students study only Mathematics?
A) 1
B) 2
C) 3
D) Data insufficient
E) None of these. 

2. How many students study either Physics and Mathematics or Chemistry and Biology?
A)67
B)99
C) 53
D) 60
E) None of these.

Directions for Ques(3-7): These questions are based on the pie-charts which give statistics of International students pursuing post graduation in the US in the year 2000.

 Total number of International students pursuing PG in US in the given year is 80,000.




3. What % do students from India and China form of the students from all the other countries (excluding others) given in the pie chart?
A)96.78%
B)95.12%
C)95.65%
D)92.01%
E) None of these.

4.How many students from the country which has the maximum representation in the year 2000 are pursuing a management course? (assuming that the nation wise distribution of the students of each graduation stream is as per the graph of distribution nationality)
A) 7200
B) 9000
C) 19200
D) cannot be determined
E) None of these.

5. If the number of students pursuing PG in USA in the year 2000 from Spain and Portugal is 25% of the number of domestic students pursuing MS in USA, then what is the total number of domestic students pursuing MS in USA?
A)16000
B)36000
C) 60000
D) 65000
E)  None of these.

6. If it is known that a total of 3,60,000 students are pursuing PG in USA in 2000, then approximately what % of it is composed of students from Asian countries, (i.e., China, India, South Korea, Philippines and Hong Kong) ?
A)16.5%
B)13.5%
C) 19%
D) 20 %
E) cannot be determined

7. What is the number of Indian students pursuing either Engineering or Management as aa % of the number of Chinese students pursuing any course other than engineering and management in USA in the year 2000? (use data given in question 4)
A)120%
B)220%
C) 360%
D) 440%
E) None Of these.

8.If the letters of the word ARISE are arranged in a row in all possible ways and the arrangements are listed in alphabetical order as in a dictionary, then the rank of the word RAISE is
(A) 51
(B) 75
(C) 76
D) 68
E) None of these.

9.  Two cards are drawn together from a pack of 52 cards. The probability that one is a club and one is a diamond?
A) 13/52
B) 13/102
C) 13/51
D) 1/3
E) None of these.

10 . A bag contains 4 black, 5 yellow and 6 green balls. Three balls are drawn at random from the bag. What is the probability that all of them are yellow?
A) 1/91
B) 2/81
C) 2/91
D) 5/81
E) None of these.


Answers
1. B 2. C 3. C 4. A 5. D 6. B 7. C 8. D 9. B 10. C
Explanations
1.64-(5+8+6+13+7+14+9)=2
2. Physics and Maths= 5+6+7+9=27
Bio and Chem= 13+7+11+2=33
Maths, Physics, Chemistry and Biology= 7
So 27+33-7=53

3. Students from China and India = 20+24= 44%.......A
Students from all countries in the graph except “others” category= 46%........B
“A”  as a percentage of “B”= (44/46)*100=95.65%

4. The country with the maximum representation in 2000 is India. Number of students from India= (80,000*24)/100=19200
Students from India taking up management = (19200*135)/360=7200

5. Portugal + Spain = 20% =(80,000*20)/100 = 16000
16000 is 25% of domestic students pursuing MS in USA, so Domestic students pursuing MS in USA=64000

6. Students of Asian Countries comprise =24+20+7+6+4=61%
Students of Asian countries comprise=(80,000*61)/100= 48800
So 48800 as a % of 3,60,000 is (48800/360000)*100=13.5%

7.Indian students  pursuing Engg on MGMT= 24% of (80,000*(270/360))…..A
Chinese students pursuing other courses=20% of (80000*(90/360))……….B
A as a % of B=360%

8.  The alphabetical order of the letters of the word ARISE is A,E,I,R,S.
The number of words which begin with A,E,I,RAE,RAIE are resp 4!, 4!, 4!, 2!, 1!. The next word is the required word.
Hence rank of  the word RAISE is 24+24+24+2+1+1=76

9. (B) Required Probability = (13c1* 13c1)/ 52c2 =  13/102
10. (C) Total number of balls = 4 + 5 + 6 = 15
Required Probability = 5c3/15c3 = 2/91


This Quiz is provided by one of our ardent BA Reader Pyari Chhutki  :-) Thank You Pyari Chhutki 
We wish you all the very best for future.



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