Q1)-Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively
Q2)-The greatest number by which the product of three consecutive multiples of 3 is always
Q3)-Average of 10 matches is 32, How many runs one should should score to increase his average by 4 runs.
Q4)-Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages.
Q5)-What will be vulgar fraction of 0.0056
Q6)-Rahul's Mathematics test had 75 problems, 10 arithmetic, 30 algebra, 35 geometry problems. Although he answered 70% of arithmetic, 40% of arithmetic and 60% of geometry problems correctly, still he got less than 60% problems right. How many more questions he would have to answer more to get passed ?
Q7)-Alfred buys an old scooter for Rs. 4700 and spends Rs. 800 on its repairs. If he sells the scooter for Rs. 5800, his gain percent is
Q8)-A dog takes 3 leaps for every 5 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is
Q9)-P and Q started a business investing Rs 85000 and Rs 15000 resp. In what ratio the profit earned after 2 years be divided between P and Q respectively.
Q10)-A piece of work can be done by 6 men and 5 women in 6 days or 3 men and 4 women in 10 days. It can be done by 9 men and 15 women in how many days ?
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19
17
13
9
Ans.- B
Answer will be HCF of (400-9, 435-10, 541-14)
HCF of (391, 425, 527) = 17
Answer will be HCF of (400-9, 435-10, 541-14)
HCF of (391, 425, 527) = 17
Q2)-The greatest number by which the product of three consecutive multiples of 3 is always
54
81
162
243
Ans.- C
3*6*9 = 162
3*6*9 = 162
Q3)-Average of 10 matches is 32, How many runs one should should score to increase his average by 4 runs.
70
76
78
80
Ans.- B
Average after 11 innings should be 36
So, Required score = (11 * 36) - (10 * 32)
= 396 - 320 = 76
Average after 11 innings should be 36
So, Required score = (11 * 36) - (10 * 32)
= 396 - 320 = 76
Q4)-Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages.
30
35
37
41
Ans.- B
Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.
Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.
Q5)-What will be vulgar fraction of 0.0056
7/1150
7/1175
7/1250
7/1275
Ans.- C
Q6)-Rahul's Mathematics test had 75 problems, 10 arithmetic, 30 algebra, 35 geometry problems. Although he answered 70% of arithmetic, 40% of arithmetic and 60% of geometry problems correctly, still he got less than 60% problems right. How many more questions he would have to answer more to get passed ?
4
5
6
8
Ans.- B
Number of questions attempted correctly = (70% of 10 + 40% of 30 + 60% of 35)
= 7 + 12 + 21 = 40.
Questions to be answered correctly for 60% = 60% of total quations
= 60 % of 75 = 45.
He would have to answer 45 - 40 = 5
Number of questions attempted correctly = (70% of 10 + 40% of 30 + 60% of 35)
= 7 + 12 + 21 = 40.
Questions to be answered correctly for 60% = 60% of total quations
= 60 % of 75 = 45.
He would have to answer 45 - 40 = 5
Q7)-Alfred buys an old scooter for Rs. 4700 and spends Rs. 800 on its repairs. If he sells the scooter for Rs. 5800, his gain percent is
6/19 %
6/17 %
5(5/11) %
3(5/11)%
Ans.- C
Whenever we get this type of question, we should have formula in mind that,
Gain% = (gain/cost)*100
Cost = 4700 + 800 = Rs. 5500
S.P. = Rs. 5800
Profit = 5800 - 5500 = 300
Gain%= 300/5500 * 100
5(5/11) %
Whenever we get this type of question, we should have formula in mind that,
Gain% = (gain/cost)*100
Cost = 4700 + 800 = Rs. 5500
S.P. = Rs. 5800
Profit = 5800 - 5500 = 300
Gain%= 300/5500 * 100
5(5/11) %
Q8)-A dog takes 3 leaps for every 5 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is
4:5
9:5
8:5
9:2
Ans.- B
Dog : Hare = (3*3) leaps of hare : 5 leaps of hare
= 9 : 5
Dog : Hare = (3*3) leaps of hare : 5 leaps of hare
= 9 : 5
Q9)-P and Q started a business investing Rs 85000 and Rs 15000 resp. In what ratio the profit earned after 2 years be divided between P and Q respectively.
17 : 5
17 : 3
17 : 6
17 : 7
Ans.- B
In this type of question as time frame for both investors is equal then just get the ratio of their investments.
P:Q = 85000:15000
= 85:15
= 17:3
In this type of question as time frame for both investors is equal then just get the ratio of their investments.
P:Q = 85000:15000
= 85:15
= 17:3
Q10)-A piece of work can be done by 6 men and 5 women in 6 days or 3 men and 4 women in 10 days. It can be done by 9 men and 15 women in how many days ?
3 days
4 days
5 days
6 days
Ans.- A
To calculate the answer we need to get 1 man per day work and 1 woman per day work.
Let 1 man 1 day work =x
and 1 woman 1 days work = y.
=> 6x+5y = 1/6
and 3x+4y = 1/10
On solving, we get x = 1/54 and y = 1/90
(9 men + 15 women)'s 1 days work =
(9/54) + (15/90) = 1/3
9 men and 15 women will finish the work in 3 days
To calculate the answer we need to get 1 man per day work and 1 woman per day work.
Let 1 man 1 day work =x
and 1 woman 1 days work = y.
=> 6x+5y = 1/6
and 3x+4y = 1/10
On solving, we get x = 1/54 and y = 1/90
(9 men + 15 women)'s 1 days work =
(9/54) + (15/90) = 1/3
9 men and 15 women will finish the work in 3 days
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