Q1)-A does half as much work as B in three-fourth of the time. If together they take 18 days to complete the work, how much time shall B take to do it.
Q2)-A can do a piece of work in 15 days and B alone can do it in 10 days. B works at it for 5 days and then leaves. A alone can finish the remaining work in
Q3)-A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?
Q4)-If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Q5)-A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
Q6)-4 men and 6 women finish a job in 8 days, while 3 men and 7 women finish it in 10 days. In how many days will 10 women working together finish it ?
Q7)-An employer pays Rs. 30 for each day a worker works, and forfeits Rs. 5 for each day he is idle. At the end of 60 days, a worker gets Rs. 500. For how many days did the worker remain idle?
Q8)-A man can do a piece of work in 4 days, but with the help of his daughter, he can do it in 3 days. In what time can his daughter do it alone?
Q9)-If 10 bulls can plough 20 identical fields in 3 days working 10 hours a day, then in how many days can 30 bulls plough 32 same identical fields working 8 hours a day?
Q10)-5 men and 2 boys working together can do four times as much work as a man and a boy. Working capacity of man and boy is in the ratio
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40 days
35 days
30 days
25 days
Ans.- C
Suppose B takes x dáys to do the work.
As per question A will take= 2 x 3/4 x x = 3x/2 days
(A+B)s 1 days work= 1/18
1/x + 2/3x = 1/18 or x = 30 days
Suppose B takes x dáys to do the work.
As per question A will take= 2 x 3/4 x x = 3x/2 days
(A+B)s 1 days work= 1/18
1/x + 2/3x = 1/18 or x = 30 days
Q2)-A can do a piece of work in 15 days and B alone can do it in 10 days. B works at it for 5 days and then leaves. A alone can finish the remaining work in
5 days
7.5 days
8.5 days
6 days
Ans.- B
B's 5 days work = 1/10 * 5 = 1/2
Remaining work = 1 - 1/2
A can finish work = 15 * 1/2
= 7.5 days
B's 5 days work = 1/10 * 5 = 1/2
Remaining work = 1 - 1/2
A can finish work = 15 * 1/2
= 7.5 days
Q3)-A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?
Rs. 375
Rs. 400
Rs. 600
Rs. 800
Ans.- B
C's 1 day's work = 1/3 - (1/6 + 1/8) = 1/24
A's wages : B's wages : C's wages = 1/6 : 1/8 :1/24 = 4 : 3 : 1
C's share (for 3 days) = Rs. ( 3 x 1/24 x 3200) = Rs 400
C's 1 day's work = 1/3 - (1/6 + 1/8) = 1/24
A's wages : B's wages : C's wages = 1/6 : 1/8 :1/24 = 4 : 3 : 1
C's share (for 3 days) = Rs. ( 3 x 1/24 x 3200) = Rs 400
Q4)-If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
4 days
6 days
8 days
2 days
Ans.- A
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, 6x + 8y =1/10 and 26x + 48y =1/2
Solving these two equations, we get
x = 1/100 and y = 1/200
( 15 men + 20 boy)'s 1 day's work = (15/100 + 20/100) = 1/4
15 men and 20 boys can do the work in 4 days
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, 6x + 8y =1/10 and 26x + 48y =1/2
Solving these two equations, we get
x = 1/100 and y = 1/200
( 15 men + 20 boy)'s 1 day's work = (15/100 + 20/100) = 1/4
15 men and 20 boys can do the work in 4 days
Q5)-A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
23 days
37 days
37(1/2) days
40 days
Ans.- C
Whole work is done by A in ( 20 x 5/4 ) = 25 days
Now, 1/5 work is done by A and B in 3 days
Whole work will be done by A and B in ( 3 x 5) = 15 days
A's 1 day's work = 1/25, (A + B)'s 1 day's work = 1/15
B's 1 day's work = ( 1/15 - 1/25 ) = 2/75
So , B alone would do the work in 75/2 days = 37(1/2) days
Whole work is done by A in ( 20 x 5/4 ) = 25 days
Now, 1/5 work is done by A and B in 3 days
Whole work will be done by A and B in ( 3 x 5) = 15 days
A's 1 day's work = 1/25, (A + B)'s 1 day's work = 1/15
B's 1 day's work = ( 1/15 - 1/25 ) = 2/75
So , B alone would do the work in 75/2 days = 37(1/2) days
Q6)-4 men and 6 women finish a job in 8 days, while 3 men and 7 women finish it in 10 days. In how many days will 10 women working together finish it ?
30 days
40 days
50 days
60 days
Ans.- B
Let 1 man's 1 day work = x
and 1 woman's 1 days work = y.
Then, 4x + 6y = 1/8
and 3x+7y = 1/10
solving, we get y = 1/400 [means work done by a woman in 1 day]
10 women 1 day work = 10/400 = 1/40
10 women will finish the work in 40 days
Let 1 man's 1 day work = x
and 1 woman's 1 days work = y.
Then, 4x + 6y = 1/8
and 3x+7y = 1/10
solving, we get y = 1/400 [means work done by a woman in 1 day]
10 women 1 day work = 10/400 = 1/40
10 women will finish the work in 40 days
Q7)-An employer pays Rs. 30 for each day a worker works, and forfeits Rs. 5 for each day he is idle. At the end of 60 days, a worker gets Rs. 500. For how many days did the worker remain idle?
35
48
52
58
Ans.- C
Suppose the worker remained idle for m days. Then, he worked for (60 - m) days.
30 (60 - m) – 5m = 500
1800 – 25m = 500
25m = 1300
m = 52
So, the worker remained idle for 52 days.
Suppose the worker remained idle for m days. Then, he worked for (60 - m) days.
30 (60 - m) – 5m = 500
1800 – 25m = 500
25m = 1300
m = 52
So, the worker remained idle for 52 days.
Q8)-A man can do a piece of work in 4 days, but with the help of his daughter, he can do it in 3 days. In what time can his daughter do it alone?
6 ½ days
7 days
9 ½ days
12 days
Ans.- D
Daughter’s 1 day’s work = (1/3 – 1/4) = 1/12
Daughter alone can do the work in 12/1 = 12 days
Daughter’s 1 day’s work = (1/3 – 1/4) = 1/12
Daughter alone can do the work in 12/1 = 12 days
Q9)-If 10 bulls can plough 20 identical fields in 3 days working 10 hours a day, then in how many days can 30 bulls plough 32 same identical fields working 8 hours a day?
2
4
8
10
Ans.- A
M1*D1*W2 = M2*D2*W1
10*3*10*32 = 30*d*8*20
d = 2 days
M1*D1*W2 = M2*D2*W1
10*3*10*32 = 30*d*8*20
d = 2 days
Q10)-5 men and 2 boys working together can do four times as much work as a man and a boy. Working capacity of man and boy is in the ratio
1:2
1:3
2:1
2:3
Ans.- C
Let 1 man 1 day work = x
1 boy 1 day work = y
then 5x + 2y = 4(x+y)
=> x = 2y
=> x/y = 2/1
=> x:y = 2:1
Let 1 man 1 day work = x
1 boy 1 day work = y
then 5x + 2y = 4(x+y)
=> x = 2y
=> x/y = 2/1
=> x:y = 2:1
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